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Question 2 - Think and Reflect (Page 9) Can these distances help you find the distance AD? Using Pythagoras Theorem AD = √((𝐻𝑜𝑟𝑖𝑧𝑜𝑛𝑡𝑎𝑙 𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒)^2+(𝑉𝑒𝑟𝑡𝑖𝑐𝑎𝑙 𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒)^2 ) AD = √(𝟒^𝟐+𝟑^𝟐 ) AD = √(16+9) AD = √25 AD = √(5^2 ) AD = 5 unit

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