Fill the following pyramids [Algebra Play - Ganita Prakash] - Teachoo - Number Pyramids

part 2 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 5 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 6 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 7 - Question 1 - Page 139 - Number Pyramids - Chapter 6 Class 8 - Algebra Play (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 1 - Page 139 Fill the following pyramids:Let’s answer one by one Pyramid 1 Let’s put the unknown values as variables a, b, c, d, e, f We can go from top to bottom here f + 22 = 50 Solving f = 50 – 22 f = 28 And, c + d = f c + d = 28 Also, d + e = 22 And, 4 + a = c a + 6 = d 6 + b = e Now, adding c from (3) and d from (4) in (1) c + d = 28 (4 + a) + (a + 6) = 28 4 + 6 + a + a = 28 10 + 2a = 28 2a = 28 – 10 2a = 18 a = 18/2 a = 9 Putting a = 9 in (3) 4 + a = c 4 + 9 = c 13 = c c = 13 Putting a = 9 in (4) a + 6 = d 9 + 6 = d 15 = d d = 15 Putting d = 15 in (2) d + e = 22 15 + e = 22 e = 22 – 15 e = 7 Putting e = 7 in (5) 6 + b = e 6 + b = 7 b = 7 – 6 b = 1 So, our filled pyramid looks like Pyramid 2 We can put in unknown values and solve Our answer will be Pyramid 3 We can put in unknown values and solve Our answer will be

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.