Find the number of holes, and the triangles that remain at each step - Figure it out - Page 72

part 2 - Question 2 - Figure it out - Page 72 - Chapter 4 Class 8 - Exploring Some Geometric Themes (Ganita Prakash II - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 2 - Figure it out - Page 72 - Chapter 4 Class 8 - Exploring Some Geometric Themes (Ganita Prakash II - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 2 Find the number of holes, and the triangles that remain at each step of the shape sequence that leads to the Sierpinski Triangle.Now, Step 0: ๐‘‡_0=1 (Just the starting triangle), ๐ป_0=0 (No holes yet) Step 1: ๐‘‡_1=3 (We kept 3 out of 4), ๐ป_1=1 (We removed 1) Step 2: ๐‘‡_2=3 ร— 3=9(3^2 ),๐ป_2=1(old)+3(new)= 4 Step 3: ๐‘‡_3=3 ร— 3 ร— 3=27(3^3 ),๐ป_3=1+3+3^2= 13 Thus, Remaining Triangles: ๐‘‡_๐‘›=3^๐‘› Holes: ๐ป_๐‘›=๐ป_(๐‘›โˆ’1)+๐‘‡_(๐‘›โˆ’1) (which expands to 1+3+โ”œ 3^2+โ€ฆ+3^(๐‘›โˆ’1) ) The Formulas Thus, Remaining Triangles: ๐‘‡_๐‘›=3^๐‘› Holes: ๐ป_๐‘›=๐ป_(๐‘›โˆ’1)+๐‘‡_(๐‘›โˆ’1) (which expands to 1+3+โ”œ 3^2+โ€ฆ+3^(๐‘›โˆ’1) )

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