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Constructing 15° Angle
Last updated at February 6, 2026 by Teachoo
Constructing Regular Hexagon, Angle 60° and 6-pointed Star
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II)
- Constructing an Eye
- Constructing a Perpendicular Bisector
- Constructing angle 90°
- Construction Methods in Śulba-Sūtras
- Constructing Angle Bisectors
- Figure it out - Pag 144, 145
- Constructing Copy of an Angle
- Construction of a Line Parallel to the Given Line
- Constructing Arch Designs
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Constructing Regular Hexagon, Angle 60° and 6-pointed Star
- Figure it out - Pag 154, 155
- Tangrams
- Tiling
- Figure it out - Page 160
- Tiling the Entire Plane
Transcript
Constructing 15° Angle First we make 30°, and then its bisector Steps of Construction : Draw a ray OA. Taking O as center and any radius, draw an arc cutting OA at B. 3. Now, taking B as center and with the same radius as before, draw an arc intersecting the previously drawn arc at point C. 4. Draw the ray OD Passing through C Thus, ∠ AOD = 60° Now we draw bisector of ∠ AOD 5. Taking B and C as center, with radius more than 1/2 BC, draw arcs intersecting at E. 6. Join OE Thus, ∠ AOE = 30° Now we draw bisector of ∠ AOE Mark point P where ray OE intersects the arc Taking P and B as center , with radius more than 1/2PB, draw arcs intersecting at F. 9. Join OF Thus, ∠ AOF = 15°
