Question 2 - Figure it out - Page 63, 64 - Chapter 3 Class 7 - Finding Common Ground (Ganita Prakash II)

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Question 2 (a) Is 5 × 7 × 11 × 11 a multiple of 5 × 7 × 7 × 11 × 2?For the first number to be a "multiple" of the second, it must be bigger (or equal) and divisible by it. Comparing both numbers First number = 5 × 7 × 11 × 11 Second number = 5 × 7 × 7 × 11 × 2 We notice that First number has 11 × 11 (= 121) extra multiplied, Second number has 7 × 11 × 2 (= 154) extra multiplied So, first number is smaller Since first number is smaller, it cannot be a multiple of 2nd number Since first number is smaller, it cannot be a multiple of 2nd number Question 2 (b) Is 5 × 7 × 11 × 11 a factor of 5 × 7 × 7 × 11 × 2?For the first number to be a "factor," it must fit completely inside the second number. Comparing both numbers First number = 5 × 7 × 11 × 11 Second number = 5 × 7 × 7 × 11 × 2 We notice that Number 1 has two 11s. Number 2 has only one 11. Since Number 1 has an extra 11 multiplied, it cannot fit inside the second number Thus, first number cannot be a factor of 2nd number