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Distributive Property
Last updated at January 12, 2026 by Teachoo
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Transcript
Example 3 Expand (๐+๐)(๐^2+2๐๐+๐^2 ).Solving (๐+๐)(๐^2+2๐๐+๐^2 ) = ๐(๐^2+2๐๐+๐^2 )+๐(๐^2+2๐๐+๐^2 ) = ๐ ร ๐^2+๐ ร 2๐๐+๐ ร ๐^2+๐ ร ๐^2+๐ ร 2๐๐+๐ ร ๐^2 = ๐^3+๐ ร ๐ ร 2๐+๐๐^2+๐๐^2+๐ ร ๐ ร 2๐+๐^3 = ๐^3+๐^2 ร 2๐+๐๐^2+๐๐^2+๐^2 ร 2๐+๐^3 = ๐^๐+๐๐๐^๐ +๐๐^๐+๐๐^๐+๐๐๐^๐ +๐^๐ Adding like terms together = ๐^3+(2๐๐^2+๐๐^2)+(2๐๐^2+๐๐^2)+๐^3 = ๐^๐+๐๐๐^๐+๐๐๐^๐+๐^๐ This is a common identity (๐+๐)(๐^2+2๐๐+๐^2 )=(๐+๐) ร(๐+๐)^2 =(๐+๐)^๐ =๐^๐+๐๐๐^๐+๐๐๐^๐+๐^๐