Expand (๐‘Ž+๐‘)(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2) - Chapter 6 Class 8 - Ganita Prakash - Distributive Property

part 2 - Example 3 - Distributive Property - Chapter 6 Class 8 - We Distribute yet things Multiply (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Example 3 Expand (๐‘Ž+๐‘)(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2 ).Solving (๐‘Ž+๐‘)(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2 ) = ๐‘Ž(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2 )+๐‘(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2 ) = ๐‘Ž ร— ๐‘Ž^2+๐‘Ž ร— 2๐‘Ž๐‘+๐‘Ž ร— ๐‘^2+๐‘ ร— ๐‘Ž^2+๐‘ ร— 2๐‘Ž๐‘+๐‘ ร— ๐‘^2 = ๐‘Ž^3+๐‘Ž ร— ๐‘Ž ร— 2๐‘+๐‘Ž๐‘^2+๐‘๐‘Ž^2+๐‘ ร— ๐‘ ร— 2๐‘Ž+๐‘^3 = ๐‘Ž^3+๐‘Ž^2 ร— 2๐‘+๐‘Ž๐‘^2+๐‘๐‘Ž^2+๐‘^2 ร— 2๐‘Ž+๐‘^3 = ๐’‚^๐Ÿ‘+๐Ÿ๐’ƒ๐’‚^๐Ÿ +๐’‚๐’ƒ^๐Ÿ+๐’ƒ๐’‚^๐Ÿ+๐Ÿ๐’‚๐’ƒ^๐Ÿ +๐’ƒ^๐Ÿ‘ Adding like terms together = ๐‘Ž^3+(2๐‘๐‘Ž^2+๐‘๐‘Ž^2)+(2๐‘Ž๐‘^2+๐‘Ž๐‘^2)+๐‘^3 = ๐’‚^๐Ÿ‘+๐Ÿ‘๐’ƒ๐’‚^๐Ÿ+๐Ÿ‘๐’‚๐’ƒ^๐Ÿ+๐’ƒ^๐Ÿ‘ This is a common identity (๐‘Ž+๐‘)(๐‘Ž^2+2๐‘Ž๐‘+๐‘^2 )=(๐‘Ž+๐‘) ร—(๐‘Ž+๐‘)^2 =(๐’‚+๐’ƒ)^๐Ÿ‘ =๐’‚^๐Ÿ‘+๐Ÿ‘๐’ƒ๐’‚^๐Ÿ+๐Ÿ‘๐’‚๐’ƒ^๐Ÿ+๐’ƒ^๐Ÿ‘

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.