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Question 1 - Page 124 - Shortcut for Divisibility by 9 - Chapter 5 Class 8 - Number Play (Ganita Prakash)
Last updated at January 8, 2026 by Teachoo
Shortcut for Divisibility by 9
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
- Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
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Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
- Figure it out - Page 132, 133, 134
Transcript
Question 1 - Page 124 Using this observation, find the remainder when 427 is divided by 9.Let’s check sum of digits Sum of digits = 4 + 2 + 7 = 13 Now, dividing 13 by 9, remainder is 4 Thus, remainder is 4 when 427 is divided by 9
