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Statement 7
Last updated at January 7, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
-
Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
- Figure it out - Page 132, 133, 134
Transcript
Statement 7 If a number is divisible by both 6 and 4, it must be divisible by 24.Now, 6 & 4 have common factor 2 So, we must look at LCM of 6 & 4 LCM of 6 & 4 = 12 Thus, if a number is divisible by both 6 and 4 It will be divisible by 12 Let’s do an example Let Number = 36 Now, 36 is divisible by 6 36 is divisible by 4 36 is divisible by 12 36 is not divisible by 24 Another example could be Let Number = 48 Now, 48 is divisible by 6 48 is divisible by 4 48 is divisible by 12 48 is divisible by 24 Thus, this Statement is Sometimes True
