You are here
Statement 6
Last updated at January 7, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
-
Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
- Figure it out - Page 132, 133, 134
Transcript
Statement 6 If a number is divisible by both 9 and 4, it must be divisible by 36.Now, 9 & 4 do not have a common factor So, if a number is divisible by both 9 and 4 Number would be divisible by 9 × 4 = 36 Let’s take an example Let Number = 144 Now, 144 is divisible by 4 144 is divisible by 9 144 is divisible by 36 Thus, this Statement is Always True
