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Statement 3
Last updated at January 7, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
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Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
- Figure it out - Page 132, 133, 134
Transcript
Statement 3 If a number is divisible by 7, then all multiples of that number will be divisible by 7.Since the number is divisible by 7, it must be a Multiple of 7 So, the number is Number = 7j where j is an integer Now, we have to find all multiples of the Number Multiples of Number = Number, 2 × Number, 3 × Number,… = 7j, 2 × 7j, 3 × 7j, 4 × 7j, 5 × 7j…. Since all multiples of numbers have 7 in it, they are all divisible by 7 Hence, this Statement is Always True Let’s visualize it with examples Q3. If a number is divisible by , then all multiples of that number will be divisible by . ALWAYS TRUE Pick a base number (Divisible by 7): Explanation: Since the base brick is made of 7s, any wall you build using only those bricks will also be made of 7s.
