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Question 2 - Collinearity of 3 points by sliope - Chapter 9 Class 11 Straight Lines
Last updated at August 8, 2026 by Teachoo
Collinearity of 3 points by sliope
Chapter 9 Class 11 Straight Lines
Concept wise
- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
-
Collinearity of 3 points by sliope
- Point Slope form
- Slope-Intercept form
- Intercept form
- Normal form
- Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix
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Transcript
Question 2 In Fig 10.9, time and distance graph of a linear motion is given. Two positions of time and distance are recorded as, when T = 0, D = 2 and when T = 3, D = 8. Using the concept of slope, find law of motion, i.e., how distance depends upon time. Let A = (0, 2) , B = (3, 8) , C = (T, D) Points A,B, C lie on the line So, A, B & C are collinear Slope of AB = Slope of BC We know that slope of a line through the points (x1, y1)(x2, y2)is m = ( 2 1)/( 2 1) D 8 = 2T 6 D = 2T 6 + 8 D = 2T + 2 D = 2(T + 1) Here, we can see that as T increases , D increases Hence, Distance depends on time.
