Construct a Rectangle Whose Diagonal Divides opposite angles 50° & 40° - Construction Questions - Page 211

part 2 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 4 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 5 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 6 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 7 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Transcript

Question 1 Construct a rectangle in which one of the diagonals divides the opposite angles into 50° and 40°.Let’s make a figure For rectangle ABCD Rectangle ABCD where Diagonal AC divides it into 50° and 40° We have to assume a length of Rectangle Let Length of Rectangle = AB = 7 cm Steps of construction 1. Draw side AB of length 7 cm 2. Now, we draw 90° from point A 3. Now, we draw 90° from point B From point A - we draw 40° Where that line intersects the perpendicular from point B is point C 6. We draw 90° from point C. 7. Where that line intersects perpendicular from A is point D Thus, ABCD is our required rectangle

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo