Question 3 - Figure it out - Page 143, 144 - Chapter 6 Class 7 - Number Play - Ganita Prakash

Last updated at August 14, 2026 by

[Class 7] Here is a 2 × 3 grid. For each row and column, the parity - Figure it out - Page 143, 144

part 2 - Question 3 - Figure it out - Page 143, 144 - Chapter 6 Class 7 - Number Play - Ganita Prakash - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 3 - Figure it out - Page 143, 144 - Chapter 6 Class 7 - Number Play - Ganita Prakash - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Transcript

Question 3 Here is a 2 × 3 grid. For each row and column, the parity of the sum is written in the circle; ‘e’ for even and ‘o’ for odd. Fill the 6 boxes with 3 odd numbers (‘o’) and 3 even numbers (‘e’) to satisfy the parity of the row and column sums. Let’s name Rows and Columns and figure this out Now, Sum of Column 1 is even – so it could be e + e or o + o Let’s take o + o Sum of Column 2 is even – so it could be e + e or o + o Let’s take e + e in this case Sum of Column 3 is odd – so its either e + o or o + e Since Row 1 is odd – o + (e + e) = o + e = o So, let top right be odd Hence, bottom right would be even So, Sum of Row 2 – o + (e + 0) = o + o = e Thus, the required grid is

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