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Digits in Disguise
Last updated at October 17, 2025 by Teachoo
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 6 Class 7 - Number Play - Ganita Prakash
- Numbers can Tell us Things, Supercells
- Parity
- Figure it out - Page 131
- Small Squares in Grids (Parity in Multiplication)
- Parity of Expressions
- Some Explorations in Grids
- Magic Square
- Figure it out - Page 136
- Generalising 3 × 3 Magic Square
- First ever 4 × 4 Magic Square
- Magic Squares in History and Culture
- Virahāṅka Fibonacci Numbers
-
Digits in Disguise
- Figure it out - Page 143, 144
Transcript
Digits in Disguise We have have done arithmetic operations with numbers. Let’s do the same with letters In the calculations below, digits are replaced by letters. Each letter stands for a particular digit (0 – 9). You have to figure out which digit each letter stands for. We can do this by checking multiple digits For T = 0 0 + 0 + 0 = 0 This is not possible Similarly, T = 1, 2, 3, 4 is not possible For T = 5 5 + 5 + 5 = 15 This matches our equation Thus, T = 5, U = 1 These types of questions are called ‘cryptarithms’ or ‘alphametics’.
