[Class 7] Here is a 2 × 3 grid. For each row and column, the parity - Figure it out - Page 143, 144

part 2 - Question 3 - Figure it out - Page 143, 144 - Chapter 6 Class 7 - Number Play - Ganita Prakash - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 3 - Figure it out - Page 143, 144 - Chapter 6 Class 7 - Number Play - Ganita Prakash - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Transcript

Question 3 Here is a 2 × 3 grid. For each row and column, the parity of the sum is written in the circle; ‘e’ for even and ‘o’ for odd. Fill the 6 boxes with 3 odd numbers (‘o’) and 3 even numbers (‘e’) to satisfy the parity of the row and column sums. Let’s name Rows and Columns and figure this out Now, Sum of Column 1 is even – so it could be e + e or o + o Let’s take o + o Sum of Column 2 is even – so it could be e + e or o + o Let’s take e + e in this case Sum of Column 3 is odd – so its either e + o or o + e Since Row 1 is odd – o + (e + e) = o + e = o So, let top right be odd Hence, bottom right would be even So, Sum of Row 2 – o + (e + 0) = o + o = e Thus, the required grid is

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo