Ex 9.3, 6 - Find distance between parallel lines 15x + 8y – 34 = 0 & - Ex 9.3

part 2 - Ex 9.3, 5 (i) - Ex 9.3 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 3 - Ex 9.3, 5 (i) - Ex 9.3 - Serial order wise - Chapter 9 Class 11 Straight Lines

 

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Ex 9.3, 6 Find the distance between parallel lines 15x + 8y – 34 = 0 and 15x + 8y + 31 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = |š¶_1āˆ’ š¶_2 |/√(š“^2 + šµ^2 ) Equation of first line is 15x + 8y – 34 = 0 Above equation is of the form Ax + By + C1 = 0 where A = 15, B = 8 & C1 = āˆ’ 34 Equation of second line is 15x + 8y + 31 = 0 Above equation is of the form Ax + By + C2 = 0 where A = 15 , B = 8 , C2 = 31 Distance between parallel lines 15x + 8y – 34 = 0 and 15x + 8y + 31 = 0 is d = |š¶_1āˆ’ š¶_2 |/√(š“^2 + šµ^2 ) Putting values d = |āˆ’34 āˆ’ 31|/√(怖(15)怗^2 + (8)^2 ) d = |āˆ’34 āˆ’ 31|/√(225 + 64) d = |āˆ’65|/√289 d = 65/√(17 Ɨ 17) d = 65/17 Thus, the required distance is šŸ”šŸ“/šŸšŸ• units

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