Find equivalent fractions for the given pairs of fractions such that - Questions - Page 168 to 172

part 2 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 4 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 5 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 6 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 7 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 8 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 9 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 10 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 11 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 12 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 13 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 14 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 15 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 16 - Question (a) to (h) - Figure it out (Page 172) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Question (a) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (a) 7/2 and 3/5Basically, we need to make denominator same To do this, we multiply both denominators 2 Γ— 5 = 10 So, our fractions become πŸ•/𝟐=πŸ•/𝟐 Γ—πŸ“/πŸ“ =πŸ‘πŸ“/𝟏𝟎 πŸ‘/πŸ“=πŸ‘/πŸ“ Γ—πŸ/𝟐 =πŸ”/𝟏𝟎 Thus, our equivalent fractions are πŸ‘πŸ“/𝟏𝟎 and πŸ”/𝟏𝟎 Question (b) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (b) 8/3 and 5/6Basically, we need to make denominator same To do this, we multiply both denominators 3 Γ— 6 = 18 But, this is too big We can just do 3 Γ— 2 = 6 and only change 1st fraction Let’s do that πŸ–/πŸ‘=πŸ–/πŸ‘ Γ—πŸ/𝟐 =πŸπŸ”/πŸ” Thus, our equivalent fractions are πŸπŸ”/πŸ” and πŸ“/πŸ” Question (c) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (c) 3/4 and 3/5Basically, we need to make denominator same To do this, we multiply both denominators 4 Γ— 5 = 20 So, our fractions become πŸ‘/πŸ’=πŸ‘/πŸ’ Γ—πŸ“/πŸ“ =πŸπŸ“/𝟐𝟎 πŸ‘/πŸ“=πŸ‘/πŸ“ Γ—πŸ’/πŸ’ =𝟏𝟐/𝟐𝟎 Thus, our equivalent fractions are πŸπŸ“/𝟐𝟎 and 𝟏𝟐/𝟐𝟎 Question (d) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (d) 6/7 and 8/5Basically, we need to make denominator same To do this, we multiply both denominators 7 Γ— 5 = 35 So, our fractions become πŸ”/πŸ•=πŸ”/πŸ• Γ—πŸ“/πŸ“ =πŸ‘πŸŽ/πŸ‘πŸ“ πŸ–/πŸ“=πŸ–/πŸ“ Γ—πŸ•/πŸ• =πŸ’πŸ/πŸ‘πŸ“ Thus, our equivalent fractions are πŸ‘πŸŽ/πŸ‘πŸ“ and πŸ’πŸ/πŸ‘πŸ“ Question (e) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (e) 9/4 and 5/2Basically, we need to make denominator same To do this, we multiply both denominators 4 Γ— 2 = 8 But, this is too big We can just do 2 Γ— 2 = 4 and only change 2nd fraction Let’s do that πŸ“/𝟐=πŸ“/𝟐 Γ—πŸ/𝟐 =𝟏𝟎/πŸ’ Thus, our equivalent fractions are πŸ—/πŸ’ and 𝟏𝟎/πŸ’ Question (f) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (f) 1/10 and 2/9Basically, we need to make denominator same To do this, we multiply both denominators 10 Γ— 9 = 90 So, our fractions become 𝟏/𝟏𝟎=𝟏/𝟏𝟎 Γ—πŸ—/πŸ— =πŸ—/πŸ—πŸŽ 𝟐/πŸ—=𝟐/πŸ— Γ—πŸπŸŽ/𝟏𝟎 =𝟐𝟎/πŸ—πŸŽ Thus, our equivalent fractions are πŸ—/πŸ—πŸŽ and 𝟐𝟎/πŸ—πŸŽ Question (g) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (g) 8/3 and 11/4Basically, we need to make denominator same To do this, we multiply both denominators 3 Γ— 4 = 12 So, our fractions become πŸ–/πŸ‘=πŸ–/πŸ‘ Γ—πŸ’/πŸ’ =πŸ‘πŸ/𝟏𝟐 𝟏𝟏/πŸ’=𝟏𝟏/πŸ’ Γ—πŸ‘/πŸ‘ =πŸ‘πŸ‘/𝟏𝟐 Thus, our equivalent fractions are πŸ‘πŸ/𝟏𝟐 and πŸ‘πŸ‘/𝟏𝟐 Question (h) - Figure it out (Page 172) Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (h) 13/6 and 1/9Basically, we need to make denominator same To do this, we multiply both denominators 6 Γ— 9 = 54 But, this is too big We can just make denominator 18 Let’s do that πŸπŸ‘/πŸ”=πŸπŸ‘/πŸ” Γ—πŸ‘/πŸ‘ =πŸ‘πŸ—/πŸπŸ– 𝟏/πŸ—=𝟏/πŸ— Γ—πŸ/𝟐 =𝟐/πŸπŸ– Thus, our equivalent fractions are πŸ‘πŸ—/πŸπŸ– and 𝟐/πŸπŸ–

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo