Question 1 (Page 169) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash)

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[Ganita Prakash] In which group will each child get more chikki? - Questions - Page 168 to 172

part 2 - Question 1 (Page 169) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Question 1 (Page 169) - Questions - Page 168 to 172 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Question 1 (Page 169) In which group will each child get more chikki? 1 chikki divided between 2 children or 5 chikkis divided among 8 children.First group 1 chikki divided between 2 children Each child gets = (š‘‡š‘œš‘”š‘Žš‘™ š‘ā„Žš‘–š‘˜š‘˜š‘–)/(š‘‡š‘œš‘”š‘Žš‘™ š‘ā„Žš‘–š‘™š‘‘š‘Ÿš‘’š‘›) = šŸ/šŸ Second group 5 chikki divided between 8 children Each child gets = (š‘‡š‘œš‘”š‘Žš‘™ š‘ā„Žš‘–š‘˜š‘˜š‘–)/(š‘‡š‘œš‘”š‘Žš‘™ š‘ā„Žš‘–š‘™š‘‘š‘Ÿš‘’š‘›) = šŸ“/šŸ– Now, we need to compare šŸ/šŸ and šŸ“/šŸ– To compare, we make denominator same So, šŸ/šŸ=šŸ/šŸ ƗšŸ’/šŸ’ =šŸ’/šŸ– Thus, we need to compare šŸ’/šŸ– and šŸ“/šŸ– Since denominator is same, we compare numerator šŸ’/šŸ– < šŸ“/šŸ– We can write šŸ/šŸ < šŸ“/šŸ– Thus, in 2nd group child gets more chikki

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