Question 1 (Page 6) - Perfect Squares - and its Patterns - Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash)

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[Class 8 Maths] Using the pattern, find 36^2, given that 35^2 = 1225. - Perfect Squares - and its Patterns

part 2 - Question 1 (Page 6) - Perfect Squares - and its Patterns - Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 1 (Page 6) Using the pattern, find 362, given that 352 = 1225. To find 362, we must add the 36th consecutive odd number to 352. Finding 36th odd number The 1st odd number is 1, 2nd odd number is 3, 3rd number is 5, …, 6th odd number is 11 and so on. Thus, nth odd number would be 2n – 1 And, 36th odd number is 2(36) − 1 = 72 − 1 = 71 Calculating 362 362 = 352 + 71 = 1225 + 71 = 1296

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