Slide15.JPG

Slide16.JPG

Remove Ads

Transcript

Question 2 (b) Who am I? b. I am a number less than 100. Two of my factors are 3 and 5. One of my digits is 1 more than the other.Numbers having factor 3 & 5 would be multiples of 3 & 5 i..e Number would be multiple of 3 × 5 = 15 Finding multiples of 15 which are less than 100 15 × 1 = 15 15 × 2 = 30 15 × 3 = 45 15 × 4 = 60 15 × 5 = 75 15 × 6 = 90 15 × 7 = 105 So, possible numbers could be 15, 30, 45, 60, 75 or 90 Now, given that One of my digits is 1 more than the other Only number 45 fits the bill ∴ Our answer is 55

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo