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Ex 9.4
Ex 9.4, 2 Important Deleted for CBSE Board 2023 Exams
Ex 9.4, 3 Deleted for CBSE Board 2023 Exams
Ex 9.4.4 Important Deleted for CBSE Board 2023 Exams
Ex 9.4, 5 Deleted for CBSE Board 2023 Exams
Ex 9.4, 6 Important Deleted for CBSE Board 2023 Exams
Ex 9.4, 7 Important Deleted for CBSE Board 2023 Exams
Ex 9.4, 8 Deleted for CBSE Board 2023 Exams
Ex 9.4, 9 Important Deleted for CBSE Board 2023 Exams You are here
Ex 9.4, 10 Deleted for CBSE Board 2023 Exams
Ex 9.4
Last updated at March 22, 2023 by Teachoo
Ex 9.4, 9 Find the sum to n terms of the series whose nth terms is given by n2 + 2n Given an = n2 + 2n Now, sum of n terms is Now, = 2 + 4 + 8 + + 2n This is GP with first term A = 2 & common ratio R = 4/2 = 2 We know that sum of n term in GP Sn = ( (R^n 1))/(R 1) Putting values Now from (1) Putting values = (n(n+1)(2n+1))/6 + 2(2n 1) Thus, the required sum is (n(n+1)(2n+1))/6 + 2(2n 1)