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Checking Kaprekar’s constant for number 2025
Last updated at Aug. 29, 2025 by Teachoo
The Magic Number of Kaprekar
Class 6 (Ganita Prakash & Old NCERT)
Chapter 3 Class 6 - Number Play (Ganita Prakash)
- Numbers can Tell us Things, Supercells,
- Supercells
- Supercells in a grid (Page 58)
- Patterns of Numbers on the Number Line, Playing with Digits
- Playing with Digits
- Pretty Palindromic Patterns
-
The Magic Number of Kaprekar
- Clock and Calendar Numbers
- Figure it out - Page 64, 65
- Mental Math
- Playing with Number Patterns, and Collatz Conjecture!
- Simple Estimation
- Estimate the answer - Page 70, 71
- Games and Winning Strategies
- Figure it out - Page 72, 73
- Teachoo Questions - MCQs
- Teachoo Questions - Mix
- Teachoo Questions - Assertion Reasoning
- Teachoo Questions - Case Based
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Transcript
Checking Kaprekar’s constant for number 2025 Arrange the digits to create the largest and smallest possible numbers. Largest number (A): 5220 Smallest number (B): 0225 Subtract the smaller number from the larger one. 5220 – 0225 = 5220 – 225 = 4995 2. Repeat the process with the new number (4995). Largest number: 9954 Smallest number: 4599 Subtraction: 9954 - 4599 = 5355 3. Repeat again with the new number (5355). Largest number: 5553 Smallest number: 3555 Subtraction: 5553 - 3555 = 1998 4. Repeat again with the new number (1998). Largest number: 9981 Smallest number: 1899 Subtraction: 9981 - 1899 = 8082 5. Repeat again with the new number (8082). Largest number: 8820 Smallest number: 0288 Subtraction: 8820 - 288 = 8532 6. Repeat again with the new number (8532). Largest number: 8532 Smallest number: 2358 Subtraction: 8532 - 2358 = 6174 Thus, after 6 rounds, we have arrived at 6174, Kaprekar's constant.
