Ex 9.1, 10 - Find 20th term an = n(n - 2)/(n + 3) - Ex 9.1

  1. Chapter 9 Class 11 Sequences and Series
  2. Serial order wise
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Ex9.1 , 10 Find the 20th term in the following sequence whose nth term is an =" " (n(n−2))/(n+3) ; We need to find a20 an =" " (n(n−2))/(n+3) Putting n = 20 a20 = (20(20−2))/(20+3) = (20(18))/23 = 360/23 Hence the 20th term is 360/23

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  • Himanshu Pachauri's image
    Himanshu Pachauri
    July 12, 2017, 11:54 a.m.
    किसी समांतर श्रेणी के p पदों का योग p स्क्वायर 10 p हो तो श्रेणी के प्रथम 4 पद तथा सर्व अंतर ज्ञात करो
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