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Question 6 - Quadaratic equation - Chapter 4 Class 11 Complex Numbers
Last updated at December 16, 2024 by Teachoo
Chapter 4 Class 11 Complex Numbers
Concept wise
-
Quadaratic equation
- Two complex numbers equal
- Convert to a + ib form
- Identities (square, cube of 2 complex numbers)
- Division
- Power of i(odd and even)
- Conjugate
- Modulus,argument
- Polar representation
- Proof- Replacing iota with -iota
- Proof- Taking general complex numbers
- Proof- Solving
- Proof- Using modulus conjugate property (Pg 102)
Transcript
Ex5.3, 6 Solve the equation š„2 ā š„ + 2 = 0 x2 ā x + 2 = 0 The above equation is of the form šš„2 + šš„ + š = 0 Where a = 1 , b = ā1 , c = 2 x = (āš Ā± ā( š^2 ā4šš ))/2š x = (ā(ā1) Ā± ā((ā1)^2 ā 4 Ć 1 Ć 2))/(2 Ć 1) = (1 Ā± ā(1ā8))/2 = (1 Ā± ā(ā7))/2 = (1 Ā± ā(ā1 Ć 7))/2 = (1Ā± ā(ā1) Ćā7)/2 = (1 Ā± ā7 š)/2 Thus, š„ = (1 Ā± ā7 š)/2
