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Ex 5.3, 2 - Chapter 5 Class 11 Complex Numbers - Part 2

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Question 2 Solve the equation 2š‘„2 + š‘„ + 1 = 0 2x2 + x + 1 = 0 The above equation is of the form š‘Žš‘„2 + š‘š‘„ + š‘ = 0 Where a = 2 , b = 1 , c = 1 š‘„ = (āˆ’š‘ ± √( š‘^2 āˆ’ 4š‘Žš‘ ))/2š‘Ž = (āˆ’1 ± √((1)^2 āˆ’ 4 Ɨ 2 Ɨ 1))/(2 Ɨ 2) = (āˆ’1± √(1 āˆ’ 8))/4 = (āˆ’1± √( āˆ’ 7))/4 = (āˆ’1 ± √(āˆ’1 Ɨ 7))/4 = (āˆ’1 ± √(āˆ’1 Ɨ 7))/4 = (āˆ’1 ± √(āˆ’1 )Ɨ √7)/4 = (āˆ’1 ± √7 š‘–)/4 Thus, š‘„ = (āˆ’1 ± √7 š‘–)/2

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