Misc 6 - Chapter 2 Class 11 Relations and Functions (Term 1)
Last updated at Jan. 28, 2020 by Teachoo
Chapter 2 Class 11 Relations and Functions (Term 1)
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Misc 6 Let f = {("x, " π₯2/(1+π₯2)) : x β R } be a function from R into R. Determine the range of f. f = { ("x , " π₯2/(1+π₯2)) : x β R } We find different values of π₯2/(1 + π₯2) for different values of x Domain Value will always be between 0 & 1 We note that Value of range y = π₯2/(1 + π₯2) is always positive Also, it is always between 0 and 1 Hence, Range is any positive integer between 0 and 1 with 0 included Thus, Range of f = [0, 1)
