Relations and Functions Class 11

Master Relations and Functions Class 11 with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

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NCERT Solutions

Relations and Functions Class 11 – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Ex 2.1

12 questions

Ex 2.1, 1

Ex2.1,1 teachoo
x 2 51 a
If G +1y -2) = G5) , find the values of x and y.
x 2 5 1
G+ry -3)=G3)
Since the ordered pairs are equal, corresponding elements are equal.
Hence
201
X4425 V-353
3 +1= 3 3° 3
x 5 1,2
37a t Y=3"3
x_2 3
3.3 Y"3
x=2 y=1

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Ex 2.1, 2

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Ex 2.1, 2
If the set A has 3 elements and the set B = {3, 4, 5}, then find the
number of elements in (A x B)?
Number of elements in set A = 3
Number of elements inset B=3 (Given set B = {3, 4, 5})
Number of elements in set A x B
= Number of elements in set A x Number of elements in set B
=3x3
=9
Thus, the number of elements in (A x B) is 9.

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Ex 2.1, 3

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Ex 2.1, 3
If G = {7, 8} and H = {5, 4, 2}, find G x Hand HxG.
G ={7, 8}
and H = {5, 4, 2}
GxH={7, 8}x {5, 4, 2}
Gx H = {(7, 5),(7, 4), (7, 2),(8, 5),(8, 4), (8, 2) }
Hx G={5, 4, 2} x {7, 8}
Hx G={(5, 7),(5, 8), (4, 7),(4, 8),(2, 7), (2, 8) }

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Ex 2.1, 4 (i)

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Ex 2.1, 4
State whether each of the following statements are true or false. If
the statement is false, rewrite the given statement correctly.
{i) If P= {m, n} and Q={1n, m}, then P xQ = {(m, n)},{n, m)}.
P={m,n}
Q={n, m}
‘Px Q= {m, n} x {n, m}

= {(m, n), (m, m),

(n, n), (n, m)}

Hence. Px Q # {(m,n),{n, m)}.
Hence, the given statement is False

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Ex 2.1, 4 (ii)

State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly.
(ii) If A and B are non-empty sets, then A × B is a non-empty set of ordered pairs (x, y) such that x ∈ A and y ∈ B.

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Ex 2.1, 4 (iii)

State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly.
(iii) If A = {1, 2}, B = {3, 4}, then A × (B ∩ φ) = φ

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Ex 2.1, 5

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Ex 2.1,5
If A={-1, 1}, find AXAXA.
AxAxA= 13x11 xC1L 1
= {(-1, -1, -1), (-1, -1, 1),

(-1,1,-1), (-1,1,1),

(1,-1,-1), (1,-1,1),

(1,1,-1), (1,1, 1}

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Ex 2.1, 6

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Ex 2.1, 6
If Ax B= {{a, x), (a, y), (b, x), (b, y)}. Find A and B.
Given A x B = {(a, x), (a, y), (b, x), (b, y)}
Ais the set of all first elements
i.e. A={a,b} (Since first element contains only a and b)
and
B is the set of all second elements.
B= {x, y} (Since second element contains only x and y)

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Ex 2.1, 7

Ex 2.1, 7 teachoo.com
Let A = {1, 2}, B={1, 2, 3, 4}, C={5, 6}and D ={5, 6, 7, 8}. Verify that
(i) Ax(BOC)=(AxB)N(AxC
L.H.S R.H.S
Ax(BNC) (Ax B) 9 (Ax C)
AxB={1,2 1,2,3,4
BAC xB={1,2}x{ }
= {(1, 1), (1, 2), (1, 3), (1, 4),
=(1,2,3,4} 05, 6} {(1, 1), (1, 2), (1, 3), (1 4)
(2, 1), (2, 2), (2, 3), (2, 4)}
=
AxC=({1, 2} x {5, 6}
Ax{B OC) ={ (1,5), (1, 6),
={L xo (2, 5), (2, 6)}
=o
(Ax B) 9 (AxC)
=@

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Ex 2.1, 8

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Ex 2.1, 8
Let A= {1, 2} and B = {3, 4}. Write A x B. How many subsets
will A x B have? List them.
A= {1,2} & B= {3, 4}
Ax B= {(1, 3), (1, 4), (2, 3), (2, 4)}
No of elements of Ax B=n=4
Number of subsets of Ax B= 2"

=24

=2x2x2x?

=16
Therefore, the set A x B has 24 = 16 subsets.

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Ex 2.1, 9

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Ex 2.1,9
Let A and B be two sets such that n(A) = 3 and n (B) = 2. If
(x, 1}, (y, 2), (z, 1) are in A x B, find A and B, where x, y and z
are distinct elements.
Ax B contains (x, 1), (y, 2), (z, 1)
Ais the set of all first elements
ie. A= {x, y, Z} (Since first element contains x, y and z)
and
B is the set of all second elements.
B = {1, 2} (Since second element contains only 1 and 2)

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Ex 2.1, 10

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Ex 2.1, 10
The Cartesian product A x A has 9 elements among which
are found (—1, 0} and (0, 1). Find the set A and the
remaining elements of A x A.
Since A x A has 9 elements
So, A would have 3 elements (As 3 x 3 = 9)
Let A = {a, b, c}
Now, A x A = {a, b, c} x {a, b, c}
= { (a, a), (a, b), (a, ¢),
(b, a), (b, b), (b, c),
{c, a), (c, b), (c, c}}

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Ex 2.2

9 questions

Ex 2.2, 1

Ex 2.2, 1 teachoo
Let A = {1, 2, 3, ..., 14}. Define a relation R from A to A by R = {{x, y):
3x—y = 0, where x, y € A}. Write down its domain, codomain and
range.
= 3x x,yEA
It is given that u y
1 3x1 =3 Yes
3x-y=0
2 3x2 =6 Yes
3x=y 3 3x3 =9 Yes
y= 3x 4 3x4 =12 Yes
S 3xS =15 No
6 3x6 =18 No
Finding Relation R 7 3x7 =21 No
First, we check which values of x, y is in set A
If both x and y are in set A, then (x, y) ER

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Ex 2.2, 2

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Ex 2.2, 2
Define a relation R on the set N of natural numbers by R = {(x, y): y =x
+5,x is a natural number less than 4; x, y € N}. Depict this
relationship using roster form. Write down the domain and the range.
Given y=x+5
Also, x is a natural number less than 4
Hence, x is 1, 2, and 3.
ra

1 14+5=6

2 2+5 =7

3 3+5 =8
Hence, R = {(1, 6), (2, 7), (3, 8)}

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Ex 2.2, 3

Ex 2.2, 3 teackoo.com
A ={1, 2, 3, 5}and B = {4, 6, 9}.
Define a relation R from A to B by R = {(x, y): the difference between
x and y is odd; x € A, y € B}. Write R in roster form.
Given A=({1,2, 3,5} & B= {4, 6, 9}
Here, xEA&y EB
It is given that difference between x and y is odd
Hence, various combinations possible are
Value of y | Difference (y—x) | Whether difference odd
1 4 4-1=3 Yes
1 6 6-1=5 Yes
1 9 9-1=8 No
2 4 4-2=2 No
2 6 6-2=4 No

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Ex 2.2, 4

2.2, 4 teachoo.com
The given figure shows a relationship between the sets P and Q.
write this relation P °
{i) in set-builder form
|
Note that (4
5-3=2
6-4=2
7-5=2
So, difference of elements is 2
Let the elements of set P can be denoted by x i.e. x € P
& the elements of set Q can be denoted by yi.e. yEQ

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Ex 2.2, 5

Ex 2.2, 5 teachoo.com
Let A = {1, 2, 3, 4, 6}. Let R be the relation on A defined by {(a, b): a, b
EA, bis exactly divisible by a}.
(i) Write R in roster form
A={1, 2, 3, 4, 6}
a,bEA
Also, b is exactly divisible by a
Pasa eet) [are
1 1 : =1 Yes
1 2 222 Yes
1
1 3 : =3 Yes
1 4 ¢ =4 Yes
1 6 =6 Yes

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Ex 2.2, 6

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Ex 2.2, 6
Determine the domain and range of the relation R defined by
R= {(x, x +5): x € {0, 1, 2, 3, 4, 5}}.
xis between 0 to 5
Px] x+s

o oO+5 =5

1 1+5 =6

2 2+5 =7

3 3+5 =8

4 44+5 =9

5 5+5 =10
R= {(O, 5), (1, 6), (2, 7), (3, 8), (4, 9), (5, 10)}

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Ex 2.2, 7

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Ex 2.2,7 "
Write the relation
R = {(x, x3): x is a prime number less than 10} in roster form.
Prime numbers = 2, 3, 5, 7, 11, 13, 17
Prime numbers less than 10 = 2, 3, 5, 7
So, value of x = 2, 3,5, 7

2 23 =2x2x2 =8

3 33 =3x3x3 =27

5 53 =5x5x5 =125

7 Po=7X7x7 =343
Hence,
R = {(2, 8), (3, 27), (5, 125), (7, 343)}

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Ex 2.2, 8

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Ex 2.2,8
Let A = {x, y, z} and B = {1, 2}. Find the number of relations from A to B.
Given A = {x y, z} & B = {1, 2}
Number of relations from A to B = 2Number of elements in Ax 8

= 2Number of elements in set A x Number of elements in set B

= 2na) x n{B)
Number of elements in set A = 3
Number of elements in set B = 2
Number of relations from A to B = 2A) * "(8)

= 932

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Ex 2.2, 9

Ex 2.2, 9 teackoo.com
Let R be the relation on Z defined by
R = {{a, b): a, b € Z, a— bis an integer}. Find the domain and range of R,
Given a, b are integers, i.e. a,b EZ
As difference of integers are integers,
a-—bis an also integer
-. Domain of R = Set of all first elements in the relation
= Values of ‘a’ which are in the relation
=Zi.e. integers

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Ex 2.3

10 questions

Ex 2.3, 1 (i)

Ex 2.3,1 teackhoo
Which of the following relations are functions? Give reasons. If it is
a function, determine its domain and range.
(i) {(2, 1), (5, 1), (8, 1), (11, 1), (14, 1), (17, 1)}
A relation is a function if
* Every element of first set has an image
¢ Every element of first set has only one image
Since both conditions are satisfied 5
So, this relation is a function. 5 —
— 1
11 I
14 i
17

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Ex 2.3, 1 (ii)

Which of the following relations are functions? Give reasons. If it is a function, determine its domain and range.
(ii) {(2, 1), (4, 2), (6, 3), (8, 4), (10, 5), (12, 6), (14, 7)}

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Ex 2.3, 1 (iii)

Which of the following relations are functions? Give reasons. If it is a function, determine its domain and range.
(iii) {(1, 3), (1, 5), (2, 5)}

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Ex 2.3, 2 (i)

Ex 2.3, 2 teackoo.com
Find the domain and range of the following real function:
(i) f(x) =—|x|
Here we are given a real function
Hence, both domain and range should be real numbers
Value of [x] | fo0=—tat Whether real
number
|2) =2 -2
Jap=1 -1
Jo] =o 0
J-1] =1 -1
|-2| =2 -2
Here, x can be any Here, f(x) will always be
real number negative or zero.
All these are real values

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Ex 2.3, 2 (ii)

Find the domain and range of the following real function:
(ii) f(x) = √((9 −x^2))

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Ex 2.3, 3

Ex 2.3, 3 teackhoo.com
A function f is defined by f(x) = 2x — 5. Write down the values of
(i) f(0) (ii) #(7), (iii) f(-3),
Given f(x) = 2x-—5
Putting value of x in f(x)
f(0)=2x0-5 | f(7)=2x7-5 | f(-3)=2x(-3)-5
=0-5 =14-5 =-6-5
=-5 =9 =-11

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Ex 2.3, 4

teachoo.com
Ex 2.3, 4
The function ‘t’ which maps temperature in degree Celsius into
temperature in degree Fahrenheit is defined by .
9 :
t(C) = z C+ 32. Find
(i) t (0) (ii) t (28) (iii) t (-10)
Given
t(c)=2C +32
Putting C = 0,
9
t(0) = =* (0) + 32
=0+32
=32

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Ex 2.3, 5 (i)

Ex 2.3, 5 teachoo.com
Find the range of each of the following functions.
(i) f(x) = 2-3x, x ER, x>0.
Given that
x>0, (We need to make it in form 2 — 3x)
Multiplying 3 both sides
3x>O0x3
3x>0
Multiplying -1 both sides
-1x3x<-1x0
—3x<0
Adding 2 both sides
2-—3x<2+0

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Ex 2.3, 5 (ii)

Find the range of each of the following functions.
(ii) f(x) = x2 + 2, x, is a real number.

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Ex 2.3, 5 (iii)

Find the range of each of the following functions.
(iii) f(x) = x, x is a real number

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Examples

24 questions

Example 1

Example 1 teackhoo
If (x + 1, y -— 2) = (3, 1), find the values of x and y.
(x+1, y-2) = (3, 1)
Since the ordered pairs are equal, corresponding elements are equal.
Hence,

x+1=3 y-2=1

x=3-1 y=142

x=2 y=3
Therefore, x = 2, y=3

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Example 2

Example 2 teachoo.com
If P = {a, b, c} and Q = {r}, find the sets P x Q and Qx P. Are

these two products equal?

P = {a, b, c}

and Q = {r}

Px Q={a, b, c} x {r}

Px Q={(a,r), (b, 1), (c, r)}

Qx P= {r} x {a, b, c}

QxP= {(r, a), (r, b), (r, c}}

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Example 3

teackoo.com

Example 3
Let A = {1, 2, 3}, B = {3, 4} and C = {4, 5, 6}. Find
(i) Ax (BAC)
BN C= {3,4} n {4, 5, 6}

= {4}
Ax(BNOC)

= {1, 2, 3} x {4}

= {(1, 4), (2, 4), (3, 4)}

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Example 4

teackoo.co:
Example 4 oH
If P = {1, 2}, form the set P x P x P.
PxPxP= {1,2}x {1,2} {1, 2}
={(1, 1, 1), (1, 1, 2),
(1, 2, 1),(1, 2, 2),
(2, 1, 1),(2, 1, 2),
(2, 2, 1), (2, 2, 2)}

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Example 5

teachoo.com
Example 5
If R is the set of all real numbers, what cdo the cartesian products
Rx Rand Rx RXR represent?
Rx R= {(x, y}: x, y € R}
represents the coordinates of all the points in two dimensional
space
RxXRxR= {(x, y, Zz): x,y,z © R}
represents the coordinates of all the points in three-dimensional
space.

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Example 6

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Example 6
If A x B= {(p, q), (p, r), (m, q), (m, r)}, find A and B.
Given A x B = {(p, q), (p, r), (m, q), (m, r)}
Ais the set of all first elements
i.e. A= {p, m} (Since first element contains only p and m)
and
B is the set of all second elements.
B = {q, r} (Since second element contains only q and r)

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Example 7

Example 7 teackoo.com
Let A = {1, 2, 3, 4, 5, 6}. Define a relation R from A to A by
R={(x y):y=x+1}
(i) Depict this relation using an arrow diagram.
Itis given that y=x+1
Also, x, yEA

1 1+1 =2 Yes

2 2+1=3 Yes

3 3+1 =4 Yes

4 4+1=5 Yes

5 5+1 =6 Yes

6 6+1 =7 No

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Example 8

teachoo.com
Example 8
The figure shows a relation between the sets P and Q.
Write this relation
P Q
(i) in set-builder form
7]

=
<J
(3) =9
(3-9
(2? =4
(27 =4
(5)? = 25
(-S}2= 25

View solution

Example 9

Example 9
Let A = {1, 2} and B = {3, 4}. Find the number of relations from A to B.
Given A = {1,2} & B = {3,4}
Number of relations from A to B = 2Number of elements in A × B
= 2Number of elements in set A × Number of elements in set B
= 2n(A) × n(B)
Number of elements in set A = 2
Number of elements in set B = 2
Number of relations from A to B = 2n(A) × n(B)
= 22 × 2

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Example 10

Example 10 teackoo.com

Let N be the set of natural numbers and the relation R be

defined on N such that R = {(x, y) : y = 2x, x, y € N}. What is the

domain, codomain and range of R? Is this relation a function?
Value of x Value of y

Given that y=2x &x,yEN

Here, xis a always natural number,

So, Domain = Set of natural numbers = N

Here, y is always an even number

Range = Set of even natural numbers

Codomain = Set of Natural numbers = N

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Example 11 (i)

teachoo.com

Example 11
Examine each of the following relations given below and state in
each case, giving reasons whether it is a function or not?
(i) R = {(2, 1), (3, 1), (4, 2}}

In function, first element is not repeating
The first elements are 2,3 and 4
All these are not repeating.
Hence, they have unique images.
So, this relation is a function.

View solution

Example 11 (ii)

Example 11
Examine each of the following relations given below and state in each case, giving reasons whether it is a function or not?
(ii) R = {(2, 2), (2, 4), (3, 3), (4, 4)}

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Example 11 (iii)

Example 11
Examine each of the following relations given below and state in each case, giving reasons whether it is a function or not?
(iii) R = {(1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7)}

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Example 12

Example 12 teackoo.com
Let N be the set of natural numbers. Define a real valued function
f:N—>N by f (x) = 2x + 1. Using this definition, complete the table
given below.
x | 1 2 3 4 5 6 7
F1)= — f(2)= —(3)= —HAY= AOS) =—(6)= A(T) =
Given f(x) = x?
To complete the table, we put values of x in f(x)
f(1) = 2(1)+1 | £(2)=2(2)4+1 (3) = 2(3) +1 (4) = 2(4) +1
=2¢1 =44+1 =6+1 =8+1
=3 =5 =7 =9

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Example 13

Example 13 teachoo.com

Define the function f: R > R by y = f(x) = x2, x € R. Complete the

table given below by using this definition. What is the domain

and range of this function? Draw the graph of f.

pox | 4-3-2 -1 0 1 2 3 4

y = f(x) =? BE

Given f(x) = x?

To complete the table, we put values of x in f(x)
f(-4) = (4) = 16
f{-3) = (-3)=9
f(-2) = (-2)°=4
f-1)=(-4P=1

View solution

Example 14

Example 14 teachoo.com
Draw the graph of the function f :R > R defined by f {x} = x3, x E R.
f(x) =3, x ER
Also, ai —R
Domain is Range isa
arealnumber Real number
We find various values of f(x} by using different values of x
Value of y = f(x) => | Point to be plotted
ry) 0?=0x0x0 =0 (0,0)
1 =1x1x1 =1 (1,1)
2 23=2x2x2 =8 (2,8)
3 33=3x3x3=27 (3,27)
-1 (-1))=-1x-1x-1 =-1 (-1,-1)
-2 (-2)3 =-2x-2x-2 =-8 (-2, -8)
3 (-3)3 =-3x-3x-3 =-27 (-3, -27)

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Example 15

teachoo.com
Example 15
Define the real valued function f : R — {0} > R defined by f (x) = : x
€ R — {0}. Complete the Table given below using this definition.
What is the domain and range of this function?
x
v= fi) => ae
Given f(x) = -, x € R— {0}
Finding f(x) at different values of x
1
f(-2) = a
=-0.5

View solution

Example 16

Example 16 teachoo.com
Let f(x) = xand g(x) = 2x + 1 be two real functions. Find
(F+ 8) x (F8) 6) (fe) (Z) 6)
f0d = x? & g(x) = 2x41
(f + g) (x) = F(x) + g(x)

= (x?) + (2x + 1)

=x? +2x+1,
«(f+ g) (x) =92 + 2n 41

(f — g) (x) = f(x} - g(x)
= (x?) —(2x + 1)

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Example 17

Example 17 teackoo.com
Let f(x) = «/x and g(x) = x be two functions defined over the set
of nonnegative real numbers. Find (f + g) (x), (f— g) (x}, (fg) &)
f
and (5) (x)
(f + g) (x) = f(x) + g(x)
=yX+x,
(fg) (x) = f(x) — g{x)
= /x-x
(fg) x = f(x) * g(x)
= xxx
1
=x2xx!

View solution

Example 18

Example 18 teackoo.com
Let R be the set of real numbers. Define the real function f: ROR by
f(x) = x + 10 and sketch the graph of this function.
f(x) =x+10
Also, f:R >R
nomat is \ nae isa
areal number Real number
0 0+10 =10 (0, 10)
1 1+10 =11 (1, 11)
2 2+10 =12 (2, 12)
-1 -1+10 =9 (-1,9)
-2 -2+10 =8 (-2, 8)

View solution

Example 19

teachoo.com

Example 19
Let R be a relation from Q to Q defined by R= {{a, b):a,bEQ
and a —b € Z}. Show that
(i) (a, a) ER forallacQ
Given R = {(a, b): a,b € Qanda—b eZ}
Hence we can say that
(a, b) is in relation R if

1. a,b €Qi.e. botha & bare insetQ (Given)

2. a—b€Zi.e. difference of a & b is an integer
We need to prove both these conditions for {a, a)
a,a€Q,i.e.aisinsetQ

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Example 20

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Example 20
Let f = {(1, 1), (2, 3), (0, -1), (-1, -3)} be a linear function from Z into
Z. Find f(x).
Since f is a linear function,
Let f(x) =mx+c.
Putting value of x and y in the function
For (1, 1) For (2, 3)

y=mxtc y=mx+c

L=m(1}+c 3=m(2)+c

l=m+tc 3=2m+c

m+c=1 (1) am+c=3_ ..{2)

View solution

Example 21

Example 21 teackoo.com
x? + 3x45
Find the domain of the function f (x) =—;—-~——
x - 5x44
x7 43x45
f (x) = =———_
(x) x?-5x+4
— x +3x45
x? 4x —x +4
_ x? 4+ 3x45
~ x(x — 4) -1(x — 4)
_ x +3xK45
~ (@-4)(x-1)
In real numbers , the denominator cannot be zero
Hence, {x — 4) (x-—1) #0
-« x#4andx41

View solution

Example 22

teachoo.com
Example 22
The function f is defined by
i x<0
f= 41 ,x=0
x+1,x>0
Draw the graph of f {x}.
For x <0, f(x)=1-x
We find the points to be plotted when x <0
41 1-(-1)=1+1 =2 (1,2)
—2 1-(-2)=1+2 =3 ( - 2,3)
3 1-(-3)=1+3 =4 (-3,4)
-4 1-(-4)=14+4=5 (-4, 5)

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Miscellaneous

12 questions

Misc 1

Misc 1 teachoo
. . . x, OSxS3
The relation f is defined by _ f(x} = fe 3<x<10
. . . x, OSxS2
The relation gis defined by g (x) = fr 2<x<10
Show that f is a function and g is not a function.
Arelation is a function if
* Every element of first set has an image
* Every element of first set has only one image
Finding value of f(x) and g(x) for different values of x

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Misc 2

Misc 2 teackoo.com
_ f.1)- fd)
=y2 Fa a
If fo) = x2, find G41 -1)
Let us first find f(1.1) and f(1)
For f(1.1)
f(1.1} = (1.1)
=11x1.1.
=1.21
For f(1)
f(1) = 1?
=1x1=1

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Misc 3

Misc 3 teachoo.com
x? t+2x41
Find the domain of the function f (x) =—~—~———
x — 8x +412
x? + 2x41
f(x)=2 >>
x 8x +12
_— ty?
~ x? 2% —6x +12
- ty
~ x(x —2) — 6(% —2)
_— +1)?
~ (x — 6)(x —2)
In real numbers , the denominator cannot be zero
Hence {x — 6) (x-— 2) #0
=>x#6andx#2

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Misc 4

Misc 4 teachoo.com
Find the domain and the range of the real function f defined by.
f(x) = ¥(« — 1)
It is given that the function is a real function.
Hence, both its domain and range should be real numbers
Value of _ ea Whether real
x f(x) = va — 1 number
number greater 1 v1 —1=¥V0 =0 Yes
0 V0 —1=v-1 No
-1 vV-1 —1 =<V-2 No
-2 V¥—2 —1=+V-3 No
Here, f(x) is always positive,
Minimum value of f(x) is 0, Maximum can be any value

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Misc 5

Misc 5 teackoo.com
Find the domain and the range of the real function f defined
by f {x} = |x-1].
Here we are given a real function
Hence, both domain and range should be real numbers
number
2 |2-1|=|]1]=1 Yes
1 |1-1] =|0| =0 Yes
0 Jo—1| =|-1] =1 Yes
-1 J-1-1] = |-2| =2 Yes
-2 |-2-1] = |-3] =3 Yes
Here, x can Here, f(x) will always
be any be positive
real number
nr 7erp.,

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Misc 6

Misc 6 teackoo.com
Let f= {(x, =) :x€R} bea function from R into R. Determine
14+x
the range of f.
f={(x, =) :xER}
14+x x
Domain Range = =e
1
142? 141 2
We find different values ra oe
(-1)? 1 1
; 7
of — for different ae
values of x iia ill a
Value will always be
between0 &1

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Misc 7

Misc 7 teachoo.com
Let f, g: R > R be defined, respectively by f(x) = x + 1, g(x) = 2x-3.
Find f+ g, f—gand f
f(x) =x + 1, g(x) = 2x-3
(f + g) (x) = f(x) + g(x)
= (x +1) +(2x-3)
=3x-2
«.(f + g) (x) = 3x-2
(f—g) (x) = f(x) — g(x)
= (x + 1)- (2x- 3)
=xX+1-2x+3
=-x+4
«. (F-g) (xj =-x +4

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Misc 8

Misc 8 teachoo.com
Let f = {(1, 1}, (2, 3), (0, -1), (-1, -3}} be a function from Z to Z
defined by f(x) = ax + b, for some integers a, b. Determine a, b.
Given f(x) = ax+b
ie. y=axt+b
Putting values of x and y in f(x)
For (1, 1) For (2, 3)

y=axtb y=ax+b

1=a(1)+b 3=a(2)+b

l=at+hb 3=2at+b

a+b=1. ...(1) 2a+b=3 ...(2)

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Misc 9

teachoo.com

Misc 9 - Introduction
Let R be a relation from N to N defined by
R = {(a, b): a, b € Nand a = b?}. Are the following true?
(i) (a, a) ER, for allae N
Isa =a?
Checking for different values of a

1=V?=1

2#2?

343?
Hence, a= a? is not always true

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Misc 10

teackoo.com
Misc 10
Let A = {1, 2, 3, 4}, B= {1, 5, 9, 11, 15, 16} and f = {(1, 5), (2, 9),
(3, 1), (4, 5), (2, 11)}. Are the following true?
(i) fisarelation from AtoB
f = {(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)}
First elements = 1, 2, 3, 4
All the first elements are in set A
So, first element is from set A
Second elements = 5, 9, 1, 11
All the second elements are in set B
So, second element is from set B

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Misc 11

Mise 14 teachoo.com
Let f be the subset of Z x Z defined by f = {(ab, a+ b): a, b € Z}.
Is f a function from Z to Z: justify your answer.
in function, first element is not repeating

f = {(ab, a+b}: a, b € Z}
Domain Range
Finding elements in f
Also, both a & b are integers
Value ofb | Value of ab Value of a + b

0 0 0x0 =0 0+0 =0

0 1 x1 =0 o+1=1

0 2 0x2 =0 0+2 =2
f will have elements (0,0) , (0,1) , (0,2)

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Misc 12

Misc 12 teackoo.com
Let A= {9, 10, 11, 12, 13} and let f: A > N be defined by f(n) = the
highest prime factor of n. Find the range of f.
Given f(n) = Highest prime factor of n
And sincen€A , A={9, 10, 11, 12, 13}
Value of n can be only 9, 10, 11, 12, 13
Doing prime factorization Value of n | Highest prime
factor of n
3/9 2(10 14/11 2/12 13]13 9 3
3]3 5|5 1 2/6 1 10 5
1 1 3/3
1 11 1
12 3
Hence, range of f = {3, 5, 11, 13} 13 13

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Why Learn This With Teachoo?

Relations and Functions develops the ideas that connect inputs, outputs and ordered pairs. Students learn Cartesian products, relations, domain, codomain, range, real-valued functions, graphs and algebra of functions. These concepts form the basis of coordinate geometry and calculus and remain central in Class 12. Teachoo’s Class 11 Relations and Functions chapter includes NCERT exercises, examples, miscellaneous problems and concept-wise lessons for learning definitions, graphs and problem-solving methods step by step.

What do you learn in Relations and Functions?

For non-empty sets A and B, the Cartesian product A × B is the set of ordered pairs (a, b), where a belongs to A and b belongs to B. Order matters: (a, b) and (b, a) are generally different. If A has m elements and B has n elements, A × B has mn elements. This idea represents coordinates and provides the structure used to define a relation.

A relation from A to B is any subset of A × B. The domain contains the first components that actually occur, while the range contains the corresponding second components. The codomain is the entire target set B, so the range is a subset of the codomain. If A × B contains mn ordered pairs, the number of possible relations from A to B is 2^(mn).

A function is a special relation in which every element of the domain has exactly one image in the codomain. Different inputs may share an output, but one input cannot have two different outputs. Arrow diagrams, ordered pairs, formulas and graphs can all represent functions.

Students study common real functions such as identity, constant, polynomial, rational, modulus, signum and greatest integer functions. They identify domains and ranges using algebra and graphs. They also perform addition, subtraction, multiplication and division of real functions while observing restrictions, especially where a denominator becomes zero.

Topics covered on Teachoo

  • Exercises 2.1 to 2.3, NCERT examples and miscellaneous questions;

  • Cartesian products and equality of ordered pairs;

  • number of elements in Cartesian products;

  • operations on sets combined with Cartesian products;

  • definition and representation of relations;

  • finding relations from set-builder or arrow form;

  • number of possible relations;

  • definition and recognition of functions;

  • finding function values;

  • graphs of standard real functions;

  • domain and range using graphs or algebra;

  • algebra of real functions.

Learning outcomes

Students should be able to form Cartesian products, solve equations involving equal ordered pairs and count ordered pairs or relations. They should identify the domain, codomain and range of a relation, decide whether a relation is a function and evaluate functions at specified values. They should sketch or recognise basic graphs, determine domain and range and combine functions with valid restrictions.

Standard real functions and their graphs

The identity function f(x) = x has a straight-line graph through the origin. A constant function f(x) = c has a horizontal graph and range {c}. Polynomial functions are defined for all real x, while rational functions exclude values making the denominator zero. The modulus function f(x) = |x| has a V-shaped graph and non-negative range. The signum function records whether x is positive, zero or negative. The greatest integer function [x] gives the greatest integer not exceeding x and forms a step graph.

Students should learn each graph through its rule, domain, range, intercepts and symmetry. A graph represents a function of x only if every vertical line meets it at most once. This vertical-line test is a visual version of the “one output per input” definition.

A reliable domain-and-range method

For domain, begin with all real numbers and impose every restriction: exclude zero denominators, require non-negative radicands for even roots and respect any explicitly stated input set. For range, set y = f(x) and determine which y-values permit a real x, or inspect the complete graph. Squaring or clearing denominators can introduce extra possibilities, so verify the final range against the original function.

Why is this chapter important?

Functions describe how one quantity depends on another. Trigonometric functions, sequences, coordinate curves, limits and derivatives all build on this idea. Students who understand domain, range and graph behaviour here are better prepared for calculus and for application-based questions involving rules, tables and changing quantities.

How Teachoo helps you prepare

Teachoo organises the chapter in serial order for quick NCERT solution lookup and concept-wise for structured learning. Begin with ordered pairs and Cartesian products, then examine relations, and only then apply the stricter condition for a function. Use arrow diagrams to test whether each input has exactly one image.

When finding a domain, write the restrictions before simplifying: denominators cannot be zero, and expressions inside an even square root must be non-negative over the real numbers. For the range, use a graph or analyse possible output values. After the concept lessons, solve textbook and miscellaneous problems without looking at the answer, then compare each logical step.

When functions are combined, find the domains of both functions first. The domain of f + g, f − g and fg is their common domain. For f/g, additionally remove values where g(x) = 0. Record these restrictions even if algebraic simplification later cancels a factor.

School-exam, JEE and competency preparation

School exams commonly ask students to form Cartesian products, determine domains and ranges, identify functions and work with function algebra. JEE-style questions may combine multiple domain restrictions or ask students to interpret transformations of standard graphs. A strong sketch is often faster and safer than guessing from an expression.

Competency questions may give a mapping, table, machine rule or real-life input-output situation. Check completeness and uniqueness at the domain level. The fact that two inputs share an output does not stop a relation from being a function. When dividing functions, remember the domain must also exclude inputs for which the divisor function equals zero.

Common mistakes to avoid

Do not assume A × B equals B × A. Do not confuse range with codomain. A relation can omit some elements of A, but a function defined from A must assign an image to every element of A. Never cancel algebraic factors and silently restore excluded domain values. In graph questions, read the set of possible x-values and y-values separately.

Quick revision checklist

Form Cartesian products of finite sets; calculate the number of possible relations; identify domain, codomain and range in arrow diagrams; apply the vertical-line test; sketch six standard real functions; find algebraic domains and ranges; and combine two functions while stating restrictions. Verify proposed functions using the “every input, exactly one output” rule.

Deeper reasoning and concept connections

The strongest way to learn Relations and Functions is to separate three layers: the object being studied, the rule that describes it and the reason the rule works. A correct numerical result is useful, but a complete mathematical answer also explains the relationship used. Students should compare examples and non-examples, change one condition at a time and observe whether the conclusion still holds.

This chapter is part of a longer progression. Its vocabulary and representations will appear again in algebra, geometry, data, measurement or higher problem-solving. Build links deliberately: translate pictures into statements, statements into operations and operations back into a sensible interpretation. If the final result cannot be explained in ordinary language, the method has probably been followed mechanically rather than understood.

How to solve unfamiliar and competency-based questions

When a question looks new, do not search memory for an identical example. Classify it. Decide whether it asks for recognition, calculation, representation, comparison, explanation or proof. Write the relevant definition or property first. Next, organise the data and select the shortest valid method. This converts an unfamiliar surface story into a familiar mathematical structure.

Use estimation and special cases as quality checks. Test zero, one, equal values, endpoints or a simple symmetric figure whenever they are permitted. A result that violates the diagram, scale, sign, unit or expected range is a signal to recheck the setup. In multi-part cases, carry forward only verified results so one early error does not silently contaminate every later answer.

What complete mastery looks like

For Relations and Functions, a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting Relations and Functions?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in Relations and Functions?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

What makes a relation a function?

Every input in the stated domain must have one and only one output.

Are domain and range the same?

No. The domain contains allowed inputs; the range contains outputs actually produced by the function.

How should I study functions on Teachoo?

Learn the definitions and standard graphs concept-wise, then solve the NCERT exercises, examples and miscellaneous questions in serial order for complete practice.

Can two different inputs have the same output?

Yes. That still defines a function. The restriction is that one input cannot be assigned two different outputs.

Why can the range be smaller than the codomain?

The codomain contains all permitted target values, while the range contains only values actually produced by inputs from the domain.

Master the input-output idea before memorising terminology. It makes relations, functions and later calculus concepts part of one connected system.