Ex 14.1, 16 - 12 defective pens are accidentally mixed with 132 - Ex 15.1

part 2 - Ex 14.1, 16 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

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Transcript

Ex 14.1, 16 12 defective pens are accidentally mixed with 132 good ones. It is not possible to just look at a pen and tell whether or not it is defective. One pen is taken out at random from this lot. Determine the probability that the pen taken out is a good one. Total number of pens = Total defective pens + Total good pens = 12 + 132 = 144 Number of good pens = 132 P (getting a good pen) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘”๐‘œ๐‘œ๐‘‘ ๐‘๐‘’๐‘›๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘’๐‘›๐‘ ) = 132/144 = ๐Ÿ๐Ÿ/๐Ÿ๐Ÿ

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