Ex 14.1, 15 - Chapter 14 Class 10 Probability

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Ex 14.1, 15 Five cardsβˆ’βˆ’the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random. (i) What is the probability that the card is the queen? Total number of cards = 5 Number of cards that are queen = 1 P (getting a queen) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘  π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘Ÿπ‘’ π‘žπ‘’π‘’π‘’π‘›)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘ ) = 𝟏/πŸ“ Ex 14.1, 15 (ii) If the queen is drawn and put aside, what is the probability that the second card picked up is (a) an ace? (b) a queen? Total number of cards left = 4 Number of cards that are ace = 1 P (getting an ace) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘  π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘Ÿπ‘’ π‘Žπ‘π‘’)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘ ) = 𝟏/πŸ’ Number of cards that are queen = 0 P (getting a queen) = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘  π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘Ÿπ‘’ π‘žπ‘’π‘’π‘’π‘›)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘ ) = 0/4 = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.