Ex 14.1, 14 - One card is drawn from a  eck of 52 cards - Ex 15.1 - Ex 15.1

part 2 - Ex 14.1, 14 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

part 3 - Ex 14.1, 14 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

part 4 - Ex 14.1, 14 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

part 5 - Ex 14.1, 14 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

part 6 - Ex 14.1, 14 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

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Transcript

Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (i) a king of red colour Total number of cards = 52 Total number of kings of red colour = 2 P (getting a king of red colour) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘˜๐‘–๐‘›๐‘” ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘  ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘‘ ๐‘๐‘œ๐‘™๐‘œ๐‘ข๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 2/52 = ๐Ÿ/๐Ÿ๐Ÿ” Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (ii) a face card Total number of cards = 52 Face cards are King, Queen and Jack Each type has 4 cards Total number of face cards = 3 ร— 4 = 12 P (getting a face card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 12/52 = ๐Ÿ‘/๐Ÿ๐Ÿ‘ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iii) A red face card Total number of cards = 52 Face cards are King, Queen and Jack Total number Red of face cards = 6 P (getting a red face card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘Ÿ๐‘’๐‘‘ ๐‘“๐‘Ž๐‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 6/52 = ๐Ÿ‘/๐Ÿ๐Ÿ” Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iv) the jack of hearts Total number of cards = 52 We have 4 Jack cards Total number of Jack of hearts = 1 P (getting a Jack of hearts) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐ฝ๐‘Ž๐‘๐‘˜ ๐‘œ๐‘“ โ„Ž๐‘’๐‘Ž๐‘Ÿ๐‘ก๐‘  ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = ๐Ÿ/๐Ÿ“๐Ÿ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (v) a spade Total number of cards = 52 We have 4 suits โ€“ Spade, Club, Diamond and Hearts. Total number of spade cards = 13 P (getting a spade card) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ ๐‘๐‘Ž๐‘‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = 13/52 = ๐Ÿ/๐Ÿ’ Ex 14.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (vi) the queen of diamonds Total number of cards = 52 We have 4 queen cards Total number of queen of diamonds = 1 P (getting a queen of diamond) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ž๐‘ข๐‘’๐‘’๐‘› ๐‘œ๐‘“ ๐‘‘๐‘–๐‘Ž๐‘š๐‘œ๐‘›๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = ๐Ÿ/๐Ÿ“๐Ÿ

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