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Example 3 - Number of wickets taken by bowlers in one-day

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Example 3 - Chapter 14 Class 10 Statistics - Part 2

Example 3 - Chapter 14 Class 10 Statistics - Part 3
Example 3 - Chapter 14 Class 10 Statistics - Part 4

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Example 3 (Method 1 – Direct Method) The distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify? Here Class Size is not same, So, we solve by Direct Method Mean(𝑥 ̅) = (∑▒𝑓𝑖𝑥𝑖)/(∑▒𝑓𝑖) 𝑥 ̅ = 6880/45 𝑥 ̅ = 152.89 Thus, Mean signifies that on average, 45 bowlers take 152.89 wickets Example 3 (Method 2 – Step Deviation Method) The distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify? Here Class Size is not same… So, in Step Deviation Method Mean(𝑥 ̅) = a + h × (∑▒𝒇𝒊𝒖𝒊)/(∑▒𝒇𝒊) We use a value of h which can divide 𝑑𝑖 = 𝑥𝑖 − a Mean(𝑥 ̅) = a + h × (∑▒𝒇𝒊𝒖𝒊)/(∑▒𝒇𝒊) Where a = Assumed Mean Let h = Class interval Also, ∑▒𝒇𝒊 = 45 ∑▒𝒇𝒊𝒖𝒊 = −212 Putting values in formula Mean(𝒙 ̅) = a + h × (∑▒𝒇𝒊𝒖𝒊)/(∑▒𝒇𝒊) 𝑥 ̅ = 200 + 10 × (−212)/45 𝑥 ̅ = 200 – 47.11 𝒙 ̅ = 152.89 Thus, Mean signifies that on average, 45 bowlers take 152.89 wickets

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.