Ex 13.1, 3 - Daily pocket allowance of children of a locality - Ex 13.1

part 2 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics
part 3 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

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Transcript

Ex 13.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(๐‘ฅ ฬ…) = a + (โˆ‘โ–’๐’‡๐’Š๐’…๐’Š)/(โˆ‘โ–’๐’‡๐’Š) Where a = Assumed Mean h = Class interval Putting values in formula Mean = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 โˆ’ 18 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = 2๐‘“โˆ’40 2๐‘“=40 f = 40/2 f = 20

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