Ex 14.1, 3 - Daily pocket allowance of children of a locality

Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 2
Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 3

  1. Chapter 14 Class 10 Statistics (Term 2)
  2. Concept wise

Transcript

Ex 14.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(π‘₯ Μ…) = a + (βˆ‘β–’π’‡π’Šπ’…π’Š)/(βˆ‘β–’π’‡π’Š) Where a = Assumed Mean h = Class interval = 18 = 13 – 11 = 2 Putting values in formula Mean = 18 + (2𝑓 βˆ’ 40)/(44 + 𝑓) 18 = 18 + (2𝑓 βˆ’ 40)/(44 + 𝑓) 18 βˆ’ 18 = (2𝑓 βˆ’ 40)/(44 + 𝑓) 0 = (2𝑓 βˆ’ 40)/(44 + 𝑓) 0 = 2π‘“βˆ’40 2𝑓=40 f = 40/2 f = 20

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.