Mean

Chapter 14 Class 10 Statistics
Concept wise

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Ex 14.1, 8 (Method 1 β Direct Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not same, So, we solve by Direct Method Putting values in formula Mean(π₯ Μ) = (ββπππ₯π)/(ββππ) π₯ Μ = 499/40 π Μ = 12.48 Therefore, Mean number of days a student was absent is 12.48 daysEx 14.1, 8 (Method 2 β Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not sameβ¦ So, in Step Deviation Method Mean(π₯ Μ) = a + h Γ (ββππππ)/(ββππ) We use a value of h which can divide ππ = π₯π β a Mean(π₯ Μ) = a + h Γ (ββππππ)/(ββππ) Where a = Assumed Mean Let h = Class interval Also, ββππ = 40 ββππππ = β90.5 Putting values in formula Mean(π Μ) = a + h Γ (ββππππ)/(ββππ) π₯ Μ = 17 + 2 Γ (β90.5)/40 π₯ Μ = 17 β 4.525 π Μ = 12.475 Therefore, Mean number of days a student was absent is 12.48 days