Ex 13.1, 8 - A class teacher has the absentee record of - Ex 13.1 - Ex 13.1

part 2 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics
part 3 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

part 4 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics part 5 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics part 6 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

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Transcript

Ex 13.1, 8 (Method 1 โ€“ Direct Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not same, So, we solve by Direct Method ๐‘ฅ ฬ… = 499/40 ๐’™ ฬ… = 12.48 Therefore, Mean number of days a student was absent is 12.48 days Ex 13.1, 8 (Method 2 โ€“ Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Ex 13.1, 8 (Method 2 โ€“ Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Mean(๐‘ฅ ฬ…) = a + h ร— (โˆ‘โ–’๐’‡๐’Š๐’–๐’Š)/(โˆ‘โ–’๐’‡๐’Š) Where a = Assumed Mean Let h = Class interval Also, โˆ‘โ–’๐’‡๐’Š = 40 โˆ‘โ–’๐’‡๐’Š๐’–๐’Š = โˆ’90.5 Putting values in formula Mean(๐’™ ฬ…) = a + h ร— (โˆ‘โ–’๐’‡๐’Š๐’–๐’Š)/(โˆ‘โ–’๐’‡๐’Š) ๐‘ฅ ฬ… = 17 + 2 ร— (โˆ’90.5)/40 ๐‘ฅ ฬ… = 17 โ€“ 4.525 ๐’™ ฬ… = 12.475 Therefore, Mean number of days a student was absent is 12.48 days

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