Prepare Truth table for following boolean expression F = (P + Q + R')(P + Q' + R)(P' + Q + R') (P' + Q'+ R)
Answer:
F = (P + Q + R')(P + Q' + R)(P' + Q + R') (P' + Q'+ R)
Truth Table:
|
P |
Q |
R |
P’ |
Q’ |
R’ |
P + Q + R' |
P + Q' + R |
P' + Q + R' |
P' + Q'+ R |
F |
|
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
|
0 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
|
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
|
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
|
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
|
1 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
0 |
|
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
|
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
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