An element ‘M’ with electronic configuration (2, 8, 2) combines separately with (NO 3 ) , (SO 4 ) 2– and (PO 4 ) 3– radicals. Write the formula of the three compounds so formed. To which group and period of the Modern Periodic Table does the elements ‘M’ belong? Will ‘M’ form covalent or ionic compounds? Give reason to justify your answer.

 

Answer

The electronic configuration of M is 2, 8, 2

Valency of M = 2

Reaction of M with (NO 3 ) -

The valency of (NO 3 ) - is 1.

Reaction of M with ( NO3)- - Teachoo.jpg

So,the compound formed will be M(NO 3 ) 2

Reaction of M with (SO 4 ) 2-

The valency of (SO 4 ) 2- is 2.

Reaction of M with ( SO4)2- - Teachoo.jpg

 So, the compound formed will be MSO 4

Reaction of M with (PO 4 ) 3-

The valency of (PO 4 ) 3- is 3. 

Reaction of M with ( PO4)3- - Teachoo.jpg

So, the compound formed will be M 3 (PO 4 ) 2

Group and Period

Since M has a valency of 2, it belongs to Group 2.

As the number of shells is 3, M belongs to Period 3.

Covalent or Ionic compounds?

M has a tendency to donate electrons to become stable and so it forms ionic bonds

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Ask a doubt
Maninder Singh's photo - Co-founder, Teachoo

Made by

Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo