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Mix questions - Equation to be formed
Last updated at August 17, 2026 by Teachoo
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Transcript
Ex 3.6, 2 Formulate the following problems as a pair of equations, and hence find their solutions: (i) Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water & speed of the current. Let the speed of boat in still water be x km/hr & let the speed of current be y km/hr Now, Speed downstream = x + y Speed upstream = x โ y Ritu can row 20 km downstream in 2 hours For downstream Distance = 20 km Time = 2 hours Speed = x + y We know that Speed = (๐ท๐๐ ๐ก๐๐๐๐ )/๐๐๐๐ x + y = 20/2 x + y = 10 Ritu can row 4 km upstream in 2 hours For upstream Distance = 4 km Time = 2 hours Speed = x โ y We know that Speed = (๐ท๐๐ ๐ก๐๐๐๐ )/๐๐๐๐ x โ y = 4/2 x โ y = 2 Hence, our equations are x + y = 10 โฆ(1) x โ y = 2 โฆ(2) From (1) x + y = 10 x = 10 โ y Putting x = 10 โ y in (2) x โ y = 2 (10 โ y) โ y = 2 โ 2y = 2 โ 10 โ 2y = โ8 y = (โ8)/(โ2) y = 4 Putting y = 4 in (1) x + y = 10 x + 4 = 10 x = 10 โ 4 x = 6 Thus, x = 6, y = 4 is the solution Hence Speed of boat in still water = x = 6 km/hr Speed of stream = y = 4 km/hr