Ex 15.1, 11 - Eleven bags of wheat flour, each marked 5 kg - Finding probability

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Question 11 Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg): 4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00 Find the probability that any of these bags chosen at random contains more than 5 kg of flour. Number of total bags = 11 Number of bags containing more than 5 kg of flour = 7 (5.05 , 5.08 , 5.03 , 5.06 , 5.08 , 5.04 , 5.07 ) P(Bag chosen contains more than 5 kg of flour) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘”๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘š๐‘œ๐‘Ÿ๐‘’ ๐‘กโ„Ž๐‘Ž๐‘› 5๐‘˜๐‘” ๐‘œ๐‘“ ๐‘“๐‘™๐‘œ๐‘ข๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘”๐‘ ) = 7/11

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