# Question 12 - Grouped frequency - Probability

Last updated at April 16, 2024 by Teachoo

Grouped frequency

Question 12
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Last updated at April 16, 2024 by Teachoo

Question 12 The above frequency distribution table represents the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 0.16 on any of these days. Total number of days = 30 Number days for which the concentration of sulphur dioxide was in the interval of 0.12 0.16 = 2 P(concentration of sulphur dioxide as in interval 0.12 0.16) = ( 0.12 0.16)/( ) = 2/30 = 1/15