Question 1 5 (d) - Chapter 1 Class 7 Integers

Last updated at August 2, 2026 by

Ex 1.3, 5 - Chapter 1 Class 7 Integers - Part 4

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Ex 1.2, 5 Find the product, using suitable properties: (d) (– 41) × 102 (–41) × 102 = (–41) × (100 + 2) = (–41) × 100 + (–41) × 2 = –4100 – 82 = – (4100 + 82) = −4182

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