

Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at May 29, 2018 by Teachoo
Transcript
Example 7 A teacher wanted to analyze the performance of two sections of students in a mathematics test of 100 marks. Looking at their performances, she found that a few students got under 20 marks and a few got 70 marks or above. So she decided to group them into intervals of varying sizes as follows: 0 - 20, 20 - 30, . . ., 60 - 70, 70 - 100. Then she formed the following table: Make histogram of the data The data has class intervals of varying width. So, we calculate adjusted frequency Adjusted frequency = (πΉππππ’ππππ¦ Γ π πππ’ππππ π ππ§π ππ πππ‘πππ£ππ)/(πΆπ’πππππ‘ π ππ§π ππ πππ‘πππ£ππ)
Examples
Example 2
Example 3
Example 4 Important
Example 5
Example 6
Example 7 Important Not in Syllabus - CBSE Exams 2021 You are here
Example 8 Important Not in Syllabus - CBSE Exams 2021
Example 9 Not in Syllabus - CBSE Exams 2021
Example 10 Not in Syllabus - CBSE Exams 2021
Example 11 Not in Syllabus - CBSE Exams 2021
Example 12 Not in Syllabus - CBSE Exams 2021
Example 13 Not in Syllabus - CBSE Exams 2021
Example 14 Not in Syllabus - CBSE Exams 2021
Example 15 Not in Syllabus - CBSE Exams 2021
About the Author