1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise
  3. Ex 13.4

Ex 13.4, 1 (ii) - Chapter 13 Class 9 Surface Areas and Volumes (Term 2)

Last updated at Aug. 26, 2021 by

Ex 13.4, 1 - Chapter 13 Class 9 Surface Areas and Volumes - Part 2

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  1. Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
  2. Serial order wise

    3. Ex 13.4

    Ex 13.5 →

Transcript

Ex 13.4, 1 Assume = 22/7, unless stated otherwise. Find the surface area of a sphere of radius: (ii) 5.6 cm Radius of sphere = r = 5.6 cm Surface area of sphere = 4 r2 = (4 22/7 5.6 5.6)cm2 = 394.24 cm2

Chapter 13 Class 9 Surface Areas and Volumes (Term 2)
Serial order wise

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.