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Ex 13.4, 5 - A hemispherical bowl made of brass has inner - Ex 13.4

  1. Chapter 13 Class 9 Surface Areas and Volumes
  2. Serial order wise
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Ex 13.4, 5 A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2. Here we will tin-plate the inside of the hemisphere So, We need to find the curved surface area of hemisphere Radius of hemisphere = r = ๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ/2 = (10.5/2) cm = 5.25 cm Curved surface area of the hemisphere = 2๐œ‹๐‘Ÿ2 = (2ร—22/7ร—5.25ร—5.25) cm2 = 173.25 cm2 Cost of tin-plating 100 cm2 = Rs 16 Cost of tin-plating 1 cm2 = Rs 1/100 ร— 16 Cost of tin-plating 173.25 cm2 = Rs 1/100 ร— 16 ร— 173.25 = Rs 27.72 โˆด Cost of tin-plating the hemisphere is Rs 27.72

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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