# Ex 2.2, 2 (iv) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by Teachoo

Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.2, 2 Find p(0), p(1) and p(2) for each of the following polynomials: (iv) p(x) = (x – 1) (x + 1) Given p(x) = (x – 1) (x + 1) Putting x = 0 p(0) = (0 – 1) (0 + 1) = –1 × 1 = –1 Putting x = 1 p(1) = (1 – 1) (1 + 1) = 0 × 2 = 0 Putting x = 2 p(2) = (2 – 1) (2 + 1) = 1 × 3 = 3

Ex 2.2

Ex 2.2,1
Important

Ex 2.2, 2 (i)

Ex 2.2, 2 (ii)

Ex 2.2, 2 (iii)

Ex 2.2, 2 (iv) You are here

Ex 2.2, 3 (i)

Ex 2.2, 3 (ii)

Ex 2.2, 3 (iii) Important

Ex 2.2, 3 (iv)

Ex 2.2, 3 (v)

Ex 2.2, 3 (vi)

Ex 2.2, 3 (vii) Important

Ex 2.2, 3 (viii)

Ex 2.2, 4 (i)

Ex 2.2, 4 (ii)

Ex 2.2, 4 (iii) Important

Ex 2.2, 4 (iv)

Ex 2.2, 4 (v)

Ex 2.2, 4 (vi) Important

Ex 2.2, 4 (vii)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.