Ex 2.2, 2 - Chapter 2 Class 9 Polynomials - Part 7

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Ex 2.2, 2 - Chapter 2 Class 9 Polynomials - Part 8

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  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

Transcript

Ex 2.2, 2 Find p(0), p(1) and p(2) for each of the following polynomials: (iv) p(x) = (x – 1) (x + 1) Given p(x) = (x – 1) (x + 1) Putting x = 0 p(0) = (0 – 1) (0 + 1) = –1 × 1 = –1 Putting x = 1 p(1) = (1 – 1) (1 + 1) = 0 × 2 = 0 Putting x = 2 p(2) = (2 – 1) (2 + 1) = 1 × 3 = 3

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.