# Ex 2.2, 2 (ii) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by Teachoo

Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.2, 2 Find p(0), p(1) and p(2) for each of the following polynomials: (ii) p(t) = 2 + t + 2t2 – t3 Given p(t) = 2 + t + 2t2 – t3 Putting t = 0 p(0) = 2 + 0 + 2(0)2 – (0)3 = 2 + 0 + 0 – 0 = 2 Putting t = 1 p(1) = 2 + 1 + 2(1)2 – (1)3 = 2 + 1 + 2 – 1 = 4 Putting t = 2 p(2) = 2 + 2 + 2(2)2 – (2)3 = 2 + 2 + 2(4) – 8 = 2 + 2 + 8 – 8 = 4

Ex 2.2

Ex 2.2,1
Important

Ex 2.2, 2 (i)

Ex 2.2, 2 (ii) You are here

Ex 2.2, 2 (iii)

Ex 2.2, 2 (iv)

Ex 2.2, 3 (i)

Ex 2.2, 3 (ii)

Ex 2.2, 3 (iii) Important

Ex 2.2, 3 (iv)

Ex 2.2, 3 (v)

Ex 2.2, 3 (vi)

Ex 2.2, 3 (vii) Important

Ex 2.2, 3 (viii)

Ex 2.2, 4 (i)

Ex 2.2, 4 (ii)

Ex 2.2, 4 (iii) Important

Ex 2.2, 4 (iv)

Ex 2.2, 4 (v)

Ex 2.2, 4 (vi) Important

Ex 2.2, 4 (vii)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.