Ex 2.2, 2 - Chapter 2 Class 9 Polynomials - Part 3

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Ex 2.2, 2 - Chapter 2 Class 9 Polynomials - Part 4

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  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

Transcript

Ex 2.2, 2 Find p(0), p(1) and p(2) for each of the following polynomials: (ii) p(t) = 2 + t + 2t2 – t3 Given p(t) = 2 + t + 2t2 – t3 Putting t = 0 p(0) = 2 + 0 + 2(0)2 – (0)3 = 2 + 0 + 0 – 0 = 2 Putting t = 1 p(1) = 2 + 1 + 2(1)2 – (1)3 = 2 + 1 + 2 – 1 = 4 Putting t = 2 p(2) = 2 + 2 + 2(2)2 – (2)3 = 2 + 2 + 2(4) – 8 = 2 + 2 + 8 – 8 = 4

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.