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Ex 2.1, 2 (iv) - Chapter 2 Class 9 Polynomials
Last updated at May 29, 2023 by Teachoo
Ex 2.1
Ex 2.1, 1 (i)
Ex 2.1, 1 (ii)
Ex 2.1, 1 (iii) Important
Ex 2.1, 1 (iv)
Ex 2.1, 1 (v) Important
Ex 2.1, 2 (i)
Ex 2.1, 2 (ii)
Ex 2.1, 2 (iii)
Ex 2.1, 2 (iv) You are here
Ex 2.1, 3
Ex 2.1, 4 (i) Important Deleted for CBSE Board 2024 Exams
Ex 2.1, 4 (ii)
Ex 2.1, 4 (iii)
Ex 2.1, 4 (iv) Important
Ex 2.1, 5 (i)
Ex 2.1, 5 (ii)
Ex 2.1, 5 (iii)
Ex 2.1, 5 (iv)
Ex 2.1, 5 (v)
Ex 2.1, 5 (vi)
Ex 2.1, 5 (vii)
Chapter 2 Class 9 Polynomials
Serial order wise
-
Ex 2.1
- Ex 2.2
- Ex 2.3
- Ex 2.4
- Examples
- Remainder Theorem
Transcript
Ex 2.1, 2 Write the coefficients of x2 in each of the following: (iv) √2 𝑥 – 1 There is no x2 So we will create 𝑥2 in above equation by adding 0 √2 𝑥 – 1 = 0 + √2 𝑥 – 1 = 0.𝑥2 + √2 𝑥 – 1 Zero is multiplied to 𝑥2 Coefficient of 𝑥2 = 0.
