One equation of a pair of dependent linear  equations is –5x + 7y = 2. The second equation  can be: 

(a)10x + 14y + 4 = 0   (b) –10x – 14y + 4 = 0 

(c) –10x + 14y + 4 = 0   (d) 10x – 14y = − 4

One equation of a pair of dependent linear equations is –5x + 7y = 2 - MCQs from NCERT Exemplar

part 2 - Question 11 - MCQs from NCERT Exemplar - Serial order wise - Chapter 3 Class 10 Pair of Linear Equations in Two Variables

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Question 11 One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be: 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0 (c) –10x + 14y + 4 = 0 (d) 10x – 14y = − 4 Given equation −5x + 7y − 2 = 0 Therefore, a1 = −5, b1 = 7 , c1 = –2 Since we want a dependent line, it means the lines are coincident For Coincident lines 𝒂𝟏/𝒂𝟐 = 𝒃𝟏/𝒃𝟐 = 𝒄𝟏/𝒄𝟐 Since, a1 = −5 , b1 = 7 , c1 = −2 a2, b2, c2 can be a2 = −10 , b2 = 14 , c2 = −4 Thus, a coincident line is −10x + 14y − 4 = 0 10x − 14y = −4 So, the correct answer is (D)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo