Question 9 - MCQs from NCERT Exemplar - Chapter 2 Class 10 Polynomials

Transcript

Question 9 The zeroes of the quadratic polynomial x2 + 99x + 127 are: both positive (b) both negative (c) one positive and one negative (d) both equal Let p(x) = x2 + 99x + 127 Since Sum is negative but product is positive ∴ Both Zeroes are negative So, the correct answer is (B) Sum of Zeroes = (−𝒃)/𝒂 Sum of Zeroes = (−99)/1 Sum of Zeroes = −99 Product of Zeroes = 𝑪/𝑨 Product of Zeroes = 127/1 Product of Zeroes = 127