Question 1 - Polynomials Class 10
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also verify the relationship between the zeros and the coefficients in each case:
(i) 2x^3 + x^2 - 5x + 2; 1/2, 1, -2
At x = 𝟏/𝟐
p(𝟏/𝟐) = 2 (1/2)^3 + (1/2)^2
− 5 (1/2) + 2
= 1/4 + 1/4 − 5/2 + 2
= (1 + 1 − 10 + 8)/4
= 0/4
= 0
Since p(1/2) = 0
∴ 𝟏/𝟐 is a zero of p(x)
At x = 𝟏
p(1) = 2(1)3 + (1)2 – 5(1) + 2
= 2 + 1 − 5 + 2
= 5 − 5
= 0
Since p(1) = 0
∴ 1 is a zero of p(x)
At x = –2
p(-2) = 2(-2)3 + (-2)2 – 5(-2) + 2
= 16 + 4 + 10 + 2
= −16 + 16
= 0
Since p(-2) = 0
∴ –2 is a zero of p(x).
At x = 𝟏/𝟐
p(𝟏/𝟐) = 2 (1/2)^3 + (1/2)^2
− 5 (1/2) + 2
= 1/4 + 1/4 − 5/2 + 2
= (1 + 1 − 10 + 8)/4
= 0/4
= 0
Since p(1/2) = 0
∴ 𝟏/𝟐 is a zero of p(x)
Verifying relationship between zeroes and coefficients
For p(x) = 2x3 + x2 − 5x + 2
a = 2, b = 1, c = −5 and d = 2
And zeroes are
𝜶 = 1/2, 𝜷 = 1 and 𝜸 = −2
For a cubic Polynomial
p(x) = ax3 + bx2 + cx + d
With zeroes α, 𝛽 and γ
We have
𝛂 + 𝛽 + 𝛄 = (−𝒃)/𝒂
𝛂"𝛽" + 𝛽𝛄 + 𝛄𝛂 = 𝒄/𝒂
𝛂"𝛽" 𝛄= (−𝒅)/𝒂
Now
𝜶+ 𝜷 + 𝜸
= 1/2 + 1 − 2
= (1 + 2 − 4)/2
= (−1)/2
= (−𝒃)/𝒂
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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