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Transcript

Question 1 Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also verify the relationship between the zeroes and the coefficients in each case: (ii) x3 - 4x2 + 5x – 2; 2, 1, 1 Let p(x) = x3 - 4x2 + 5x – 2 Verifying zeroes At x = 2 p(2) = (2)3 βˆ’ 4 (2)2 + 5(2) βˆ’ 2 = 8 βˆ’ 4(4)+ 10 – 2 = 18 βˆ’ 18 = 0 Since p(2) = 0 ∴ 2 is a zero of p(x) At x = 𝟏 p(1) = (1)3 – 4(1)2 + 5(1) – 2 = 1 – 4 + 5 – 2 = 5 βˆ’ 5 = 0 Since p(1) = 0 ∴ 1 is a zero of p(x) At x = 𝟏 p(1) = (1)3 – 4(1)2 + 5(1) – 2 = 1 – 4 + 5 – 2 = 5 βˆ’ 5 = 0 Since p(1) = 0 ∴ 𝟏 is a zero of p(x) Verifying relationship between zeroes and coefficients. For p(x) = x3 βˆ’ 4x2 + 5x βˆ’ 2 a = 1, b = βˆ’4, c = 5 and d = βˆ’2 And Zeroes are 𝜢 = 2, 𝜷 = 1 and 𝜸 = 1 For a cubic Polynomial p(x) = ax3 + bx2 + cx + d With zeroes Ξ±, 𝛽 and Ξ³ We have 𝛂 + 𝛽 + 𝛄 = (βˆ’π’ƒ)/𝒂 𝛂"𝛽" + 𝛽𝛄 + 𝛄𝛂 = 𝒄/𝒂 𝛂"𝛽" 𝛄= (βˆ’π’…)/𝒂 Now Hence, the relationship is verified 𝜢+ 𝜷 + 𝜸 = 2 + 1 + 1 = 4 = (βˆ’(βˆ’4))/1 = (βˆ’π’ƒ)/𝒂 𝜢𝜷+ 𝜷𝜸 + 𝜸𝜢 = (2) (1) + (1) (1) + (1) (2) = 2 + 1 + 2 = 5 = 5/1 = 𝒄/𝒂 𝜢𝜷𝜸 = (2) (1) (1) = 2 = (βˆ’(βˆ’ 2))/1 = (βˆ’π’…)/𝒂

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.