Given that two of the zeroes of the cubic polynomial ax 3
ย + bx 2 + cx + d are 0, the third zero is
(a) (-b)/aย ย ย ย ย ย (b) b/aย (c) c/a ย ย (d) -d/a
MCQs from NCERT Exemplar
Last updated at August 12, 2026 by Teachoo
Transcript
Question 2 Given that two of the zeroes of the cubic polynomial ax3 + bx2 + cx + d are 0, the third zero is (a) (โ๐)/๐ (b) ๐/๐ (c) ๐/๐ (d) โ๐/๐ Let p(x) = ax3 + bx2 + cx + d Given that two zeroes are 0 โด ๐ถ = 0, ๐ท = 0 and we need to find ๐ธ We know that Sum of zeroes = (โ๐)/๐ ๐ถ + ๐ท + ๐ธ = (โ๐)/๐ 0 + 0 + ๐ธ = (โ๐)/๐ ๐ธ = (โ๐)/๐ ๐ถ + ๐ฝ + ๐พ = (โ๐)/๐ 0 + 0 + ๐พ = (โ๐)/๐ ๐ธ = (โ๐)/๐ Thus, the third zero is (โ๐)/๐ So, the correct answer is (A)